((x^4)*(y^-6))/((x^-2)(y^2))^1/2

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Solution for ((x^4)*(y^-6))/((x^-2)(y^2))^1/2 equation: 


D( x )

x = 0

(x^-2*y^2)^1 = 0

x = 0

x = 0

(x^-2*y^2)^1 = 0

(x^-2*y^2)^1 = 0

x^-2*y^2 = 0

x^-2*y^2 = 0 // : y^2

x^-2 = 0

x należy do O

x in (-oo:0) U (0:+oo)

((x^4*y^-6)/((x^-2*y^2)^1))/2 = 0

((x^4*y^-6)/(x^-2*y^2))/2 = 0

1/2*x^6*y^-8 = 0 // : 1/2*y^-8

x^6 = 0

x = 0

x in { 0} 

x belongs to the empty set

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